#113 Method Overriding and a super Call

Companies:

Sberbank

Themes:

JavaOOPCode Review

What will be printed and why?

public class Main {
    public static void main(String[] args) throws Exception {
        First first = new Second();
        first.useTest();

        Second second = new Second();
        second.useTest();
        second.callTest();
    }
}

class First {
    protected void test() {
        System.out.println("First");
    }

    public void useTest() {
        test();
    }
}

class Second extends First {
    @Override
    protected void test() {
        System.out.println("Second");
    }

    public void callTest() {
        super.test();
    }
}

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